What is 61 mod 5?

How to compute 61 mod 5?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 61 / 5 = 12.2
2. ⌊12.2⌋ = 12 (We only keep the integer part)
3. 5 × 12 = 60
4. 61 - 60 = 1 (Subtracting gives us the remainder)

In short: 61 − (5 × ⌊61 / 5⌋) = 1

Is 61 divisible by 5?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 61 mod 5 is 1, this indicates that dividing 61 by 5 leaves a remainder of 1. Therefore, no, since the remainder isn't zero, 61 is not divisible by 5.