What is 63 mod 3?

How to compute 63 mod 3?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 63 / 3 = 21
2. ⌊21⌋ = 21 (We only keep the integer part)
3. 3 × 21 = 63
4. 63 - 63 = 0 (Subtracting gives us the remainder)

In short: 63 − (3 × ⌊63 / 3⌋) = 0

Is 63 divisible by 3?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 63 mod 3 is 0, this indicates that dividing 63 by 3 leaves no remainder. Therefore, yes, 63 is indeed divisible by 3.