What is 63 mod 6?

How to compute 63 mod 6?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 63 / 6 = 10.5
2. ⌊10.5⌋ = 10 (We only keep the integer part)
3. 6 × 10 = 60
4. 63 - 60 = 3 (Subtracting gives us the remainder)

In short: 63 − (6 × ⌊63 / 6⌋) = 3

Is 63 divisible by 6?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 63 mod 6 is 3, this indicates that dividing 63 by 6 leaves a remainder of 3. Therefore, no, since the remainder isn't zero, 63 is not divisible by 6.