What is 65 mod 5?

How to compute 65 mod 5?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 65 / 5 = 13
2. ⌊13⌋ = 13 (We only keep the integer part)
3. 5 × 13 = 65
4. 65 - 65 = 0 (Subtracting gives us the remainder)

In short: 65 − (5 × ⌊65 / 5⌋) = 0

Is 65 divisible by 5?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 65 mod 5 is 0, this indicates that dividing 65 by 5 leaves no remainder. Therefore, yes, 65 is indeed divisible by 5.