What is 77 mod 6?

How to compute 77 mod 6?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 77 / 6 = 12.833333333333
2. ⌊12.833333333333⌋ = 12 (We only keep the integer part)
3. 6 × 12 = 72
4. 77 - 72 = 5 (Subtracting gives us the remainder)

In short: 77 − (6 × ⌊77 / 6⌋) = 5

Is 77 divisible by 6?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 77 mod 6 is 5, this indicates that dividing 77 by 6 leaves a remainder of 5. Therefore, no, since the remainder isn't zero, 77 is not divisible by 6.