What is 85 mod 5?

How to compute 85 mod 5?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 85 / 5 = 17
2. ⌊17⌋ = 17 (We only keep the integer part)
3. 5 × 17 = 85
4. 85 - 85 = 0 (Subtracting gives us the remainder)

In short: 85 − (5 × ⌊85 / 5⌋) = 0

Is 85 divisible by 5?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 85 mod 5 is 0, this indicates that dividing 85 by 5 leaves no remainder. Therefore, yes, 85 is indeed divisible by 5.