What is 97 mod 6?

How to compute 97 mod 6?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 97 / 6 = 16.166666666667
2. ⌊16.166666666667⌋ = 16 (We only keep the integer part)
3. 6 × 16 = 96
4. 97 - 96 = 1 (Subtracting gives us the remainder)

In short: 97 − (6 × ⌊97 / 6⌋) = 1

Is 97 divisible by 6?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 97 mod 6 is 1, this indicates that dividing 97 by 6 leaves a remainder of 1. Therefore, no, since the remainder isn't zero, 97 is not divisible by 6.