What are the numbers divisible by 1020?

1020, 2040, 3060, 4080, 5100, 6120, 7140, 8160, 9180, 10200, 11220, 12240, 13260, 14280, 15300, 16320, 17340, 18360, 19380, 20400, 21420, 22440, 23460, 24480, 25500, 26520, 27540, 28560, 29580, 30600, 31620, 32640, 33660, 34680, 35700, 36720, 37740, 38760, 39780, 40800, 41820, 42840, 43860, 44880, 45900, 46920, 47940, 48960, 49980, 51000, 52020, 53040, 54060, 55080, 56100, 57120, 58140, 59160, 60180, 61200, 62220, 63240, 64260, 65280, 66300, 67320, 68340, 69360, 70380, 71400, 72420, 73440, 74460, 75480, 76500, 77520, 78540, 79560, 80580, 81600, 82620, 83640, 84660, 85680, 86700, 87720, 88740, 89760, 90780, 91800, 92820, 93840, 94860, 95880, 96900, 97920, 98940, 99960

There is a total of 98 numbers (up to 100000) that are divisible by 1020.
The sum of these numbers is 4948020.
The arithmetic mean of these numbers is 50490.

How to find the numbers divisible by 1020?

Finding all the numbers that can be divided by 1020 is essentially the same as searching for the multiples of 1020: if a number N is a multiple of 1020, then 1020 is a divisor of N.

Indeed, if we assume that N is a multiple of 1020, this means there exists an integer k such that:

$k \times 1020 = N$

Conversely, the result of N divided by 1020 is this same integer k (without any remainder):

$k = \frac{N}{1020}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1020 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1020 less than 100000):

1 × 1020 = 1020
2 × 1020 = 2040
3 × 1020 = 3060
...
97 × 1020 = 98940
98 × 1020 = 99960