What are the numbers divisible by 1041?

1041, 2082, 3123, 4164, 5205, 6246, 7287, 8328, 9369, 10410, 11451, 12492, 13533, 14574, 15615, 16656, 17697, 18738, 19779, 20820, 21861, 22902, 23943, 24984, 26025, 27066, 28107, 29148, 30189, 31230, 32271, 33312, 34353, 35394, 36435, 37476, 38517, 39558, 40599, 41640, 42681, 43722, 44763, 45804, 46845, 47886, 48927, 49968, 51009, 52050, 53091, 54132, 55173, 56214, 57255, 58296, 59337, 60378, 61419, 62460, 63501, 64542, 65583, 66624, 67665, 68706, 69747, 70788, 71829, 72870, 73911, 74952, 75993, 77034, 78075, 79116, 80157, 81198, 82239, 83280, 84321, 85362, 86403, 87444, 88485, 89526, 90567, 91608, 92649, 93690, 94731, 95772, 96813, 97854, 98895, 99936

There is a total of 96 numbers (up to 100000) that are divisible by 1041.
The sum of these numbers is 4846896.
The arithmetic mean of these numbers is 50488.5.

How to find the numbers divisible by 1041?

Finding all the numbers that can be divided by 1041 is essentially the same as searching for the multiples of 1041: if a number N is a multiple of 1041, then 1041 is a divisor of N.

Indeed, if we assume that N is a multiple of 1041, this means there exists an integer k such that:

$k \times 1041 = N$

Conversely, the result of N divided by 1041 is this same integer k (without any remainder):

$k = \frac{N}{1041}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1041 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1041 less than 100000):

1 × 1041 = 1041
2 × 1041 = 2082
3 × 1041 = 3123
...
95 × 1041 = 98895
96 × 1041 = 99936