What are the numbers divisible by 1070?

1070, 2140, 3210, 4280, 5350, 6420, 7490, 8560, 9630, 10700, 11770, 12840, 13910, 14980, 16050, 17120, 18190, 19260, 20330, 21400, 22470, 23540, 24610, 25680, 26750, 27820, 28890, 29960, 31030, 32100, 33170, 34240, 35310, 36380, 37450, 38520, 39590, 40660, 41730, 42800, 43870, 44940, 46010, 47080, 48150, 49220, 50290, 51360, 52430, 53500, 54570, 55640, 56710, 57780, 58850, 59920, 60990, 62060, 63130, 64200, 65270, 66340, 67410, 68480, 69550, 70620, 71690, 72760, 73830, 74900, 75970, 77040, 78110, 79180, 80250, 81320, 82390, 83460, 84530, 85600, 86670, 87740, 88810, 89880, 90950, 92020, 93090, 94160, 95230, 96300, 97370, 98440, 99510

There is a total of 93 numbers (up to 100000) that are divisible by 1070.
The sum of these numbers is 4676970.
The arithmetic mean of these numbers is 50290.

How to find the numbers divisible by 1070?

Finding all the numbers that can be divided by 1070 is essentially the same as searching for the multiples of 1070: if a number N is a multiple of 1070, then 1070 is a divisor of N.

Indeed, if we assume that N is a multiple of 1070, this means there exists an integer k such that:

$k \times 1070 = N$

Conversely, the result of N divided by 1070 is this same integer k (without any remainder):

$k = \frac{N}{1070}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1070 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1070 less than 100000):

1 × 1070 = 1070
2 × 1070 = 2140
3 × 1070 = 3210
...
92 × 1070 = 98440
93 × 1070 = 99510