What are the numbers divisible by 798?

798, 1596, 2394, 3192, 3990, 4788, 5586, 6384, 7182, 7980, 8778, 9576, 10374, 11172, 11970, 12768, 13566, 14364, 15162, 15960, 16758, 17556, 18354, 19152, 19950, 20748, 21546, 22344, 23142, 23940, 24738, 25536, 26334, 27132, 27930, 28728, 29526, 30324, 31122, 31920, 32718, 33516, 34314, 35112, 35910, 36708, 37506, 38304, 39102, 39900, 40698, 41496, 42294, 43092, 43890, 44688, 45486, 46284, 47082, 47880, 48678, 49476, 50274, 51072, 51870, 52668, 53466, 54264, 55062, 55860, 56658, 57456, 58254, 59052, 59850, 60648, 61446, 62244, 63042, 63840, 64638, 65436, 66234, 67032, 67830, 68628, 69426, 70224, 71022, 71820, 72618, 73416, 74214, 75012, 75810, 76608, 77406, 78204, 79002, 79800, 80598, 81396, 82194, 82992, 83790, 84588, 85386, 86184, 86982, 87780, 88578, 89376, 90174, 90972, 91770, 92568, 93366, 94164, 94962, 95760, 96558, 97356, 98154, 98952, 99750

There is a total of 125 numbers (up to 100000) that are divisible by 798.
The sum of these numbers is 6284250.
The arithmetic mean of these numbers is 50274.

How to find the numbers divisible by 798?

Finding all the numbers that can be divided by 798 is essentially the same as searching for the multiples of 798: if a number N is a multiple of 798, then 798 is a divisor of N.

Indeed, if we assume that N is a multiple of 798, this means there exists an integer k such that:

$k \times 798 = N$

Conversely, the result of N divided by 798 is this same integer k (without any remainder):

$k = \frac{N}{798}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 798 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 798 less than 100000):

1 × 798 = 798
2 × 798 = 1596
3 × 798 = 2394
...
124 × 798 = 98952
125 × 798 = 99750