What are the numbers divisible by 799?

799, 1598, 2397, 3196, 3995, 4794, 5593, 6392, 7191, 7990, 8789, 9588, 10387, 11186, 11985, 12784, 13583, 14382, 15181, 15980, 16779, 17578, 18377, 19176, 19975, 20774, 21573, 22372, 23171, 23970, 24769, 25568, 26367, 27166, 27965, 28764, 29563, 30362, 31161, 31960, 32759, 33558, 34357, 35156, 35955, 36754, 37553, 38352, 39151, 39950, 40749, 41548, 42347, 43146, 43945, 44744, 45543, 46342, 47141, 47940, 48739, 49538, 50337, 51136, 51935, 52734, 53533, 54332, 55131, 55930, 56729, 57528, 58327, 59126, 59925, 60724, 61523, 62322, 63121, 63920, 64719, 65518, 66317, 67116, 67915, 68714, 69513, 70312, 71111, 71910, 72709, 73508, 74307, 75106, 75905, 76704, 77503, 78302, 79101, 79900, 80699, 81498, 82297, 83096, 83895, 84694, 85493, 86292, 87091, 87890, 88689, 89488, 90287, 91086, 91885, 92684, 93483, 94282, 95081, 95880, 96679, 97478, 98277, 99076, 99875

There is a total of 125 numbers (up to 100000) that are divisible by 799.
The sum of these numbers is 6292125.
The arithmetic mean of these numbers is 50337.

How to find the numbers divisible by 799?

Finding all the numbers that can be divided by 799 is essentially the same as searching for the multiples of 799: if a number N is a multiple of 799, then 799 is a divisor of N.

Indeed, if we assume that N is a multiple of 799, this means there exists an integer k such that:

$k \times 799 = N$

Conversely, the result of N divided by 799 is this same integer k (without any remainder):

$k = \frac{N}{799}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 799 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 799 less than 100000):

1 × 799 = 799
2 × 799 = 1598
3 × 799 = 2397
...
124 × 799 = 99076
125 × 799 = 99875