What are the numbers divisible by 800?

800, 1600, 2400, 3200, 4000, 4800, 5600, 6400, 7200, 8000, 8800, 9600, 10400, 11200, 12000, 12800, 13600, 14400, 15200, 16000, 16800, 17600, 18400, 19200, 20000, 20800, 21600, 22400, 23200, 24000, 24800, 25600, 26400, 27200, 28000, 28800, 29600, 30400, 31200, 32000, 32800, 33600, 34400, 35200, 36000, 36800, 37600, 38400, 39200, 40000, 40800, 41600, 42400, 43200, 44000, 44800, 45600, 46400, 47200, 48000, 48800, 49600, 50400, 51200, 52000, 52800, 53600, 54400, 55200, 56000, 56800, 57600, 58400, 59200, 60000, 60800, 61600, 62400, 63200, 64000, 64800, 65600, 66400, 67200, 68000, 68800, 69600, 70400, 71200, 72000, 72800, 73600, 74400, 75200, 76000, 76800, 77600, 78400, 79200, 80000, 80800, 81600, 82400, 83200, 84000, 84800, 85600, 86400, 87200, 88000, 88800, 89600, 90400, 91200, 92000, 92800, 93600, 94400, 95200, 96000, 96800, 97600, 98400, 99200, 100000

There is a total of 125 numbers (up to 100000) that are divisible by 800.
The sum of these numbers is 6300000.
The arithmetic mean of these numbers is 50400.

How to find the numbers divisible by 800?

Finding all the numbers that can be divided by 800 is essentially the same as searching for the multiples of 800: if a number N is a multiple of 800, then 800 is a divisor of N.

Indeed, if we assume that N is a multiple of 800, this means there exists an integer k such that:

$k \times 800 = N$

Conversely, the result of N divided by 800 is this same integer k (without any remainder):

$k = \frac{N}{800}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 800 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 800 less than 100000):

1 × 800 = 800
2 × 800 = 1600
3 × 800 = 2400
...
124 × 800 = 99200
125 × 800 = 100000