What are the numbers divisible by 801?

801, 1602, 2403, 3204, 4005, 4806, 5607, 6408, 7209, 8010, 8811, 9612, 10413, 11214, 12015, 12816, 13617, 14418, 15219, 16020, 16821, 17622, 18423, 19224, 20025, 20826, 21627, 22428, 23229, 24030, 24831, 25632, 26433, 27234, 28035, 28836, 29637, 30438, 31239, 32040, 32841, 33642, 34443, 35244, 36045, 36846, 37647, 38448, 39249, 40050, 40851, 41652, 42453, 43254, 44055, 44856, 45657, 46458, 47259, 48060, 48861, 49662, 50463, 51264, 52065, 52866, 53667, 54468, 55269, 56070, 56871, 57672, 58473, 59274, 60075, 60876, 61677, 62478, 63279, 64080, 64881, 65682, 66483, 67284, 68085, 68886, 69687, 70488, 71289, 72090, 72891, 73692, 74493, 75294, 76095, 76896, 77697, 78498, 79299, 80100, 80901, 81702, 82503, 83304, 84105, 84906, 85707, 86508, 87309, 88110, 88911, 89712, 90513, 91314, 92115, 92916, 93717, 94518, 95319, 96120, 96921, 97722, 98523, 99324

There is a total of 124 numbers (up to 100000) that are divisible by 801.
The sum of these numbers is 6207750.
The arithmetic mean of these numbers is 50062.5.

How to find the numbers divisible by 801?

Finding all the numbers that can be divided by 801 is essentially the same as searching for the multiples of 801: if a number N is a multiple of 801, then 801 is a divisor of N.

Indeed, if we assume that N is a multiple of 801, this means there exists an integer k such that:

$k \times 801 = N$

Conversely, the result of N divided by 801 is this same integer k (without any remainder):

$k = \frac{N}{801}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 801 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 801 less than 100000):

1 × 801 = 801
2 × 801 = 1602
3 × 801 = 2403
...
123 × 801 = 98523
124 × 801 = 99324