What are the numbers divisible by 808?

808, 1616, 2424, 3232, 4040, 4848, 5656, 6464, 7272, 8080, 8888, 9696, 10504, 11312, 12120, 12928, 13736, 14544, 15352, 16160, 16968, 17776, 18584, 19392, 20200, 21008, 21816, 22624, 23432, 24240, 25048, 25856, 26664, 27472, 28280, 29088, 29896, 30704, 31512, 32320, 33128, 33936, 34744, 35552, 36360, 37168, 37976, 38784, 39592, 40400, 41208, 42016, 42824, 43632, 44440, 45248, 46056, 46864, 47672, 48480, 49288, 50096, 50904, 51712, 52520, 53328, 54136, 54944, 55752, 56560, 57368, 58176, 58984, 59792, 60600, 61408, 62216, 63024, 63832, 64640, 65448, 66256, 67064, 67872, 68680, 69488, 70296, 71104, 71912, 72720, 73528, 74336, 75144, 75952, 76760, 77568, 78376, 79184, 79992, 80800, 81608, 82416, 83224, 84032, 84840, 85648, 86456, 87264, 88072, 88880, 89688, 90496, 91304, 92112, 92920, 93728, 94536, 95344, 96152, 96960, 97768, 98576, 99384

There is a total of 123 numbers (up to 100000) that are divisible by 808.
The sum of these numbers is 6161808.
The arithmetic mean of these numbers is 50096.

How to find the numbers divisible by 808?

Finding all the numbers that can be divided by 808 is essentially the same as searching for the multiples of 808: if a number N is a multiple of 808, then 808 is a divisor of N.

Indeed, if we assume that N is a multiple of 808, this means there exists an integer k such that:

$k \times 808 = N$

Conversely, the result of N divided by 808 is this same integer k (without any remainder):

$k = \frac{N}{808}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 808 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 808 less than 100000):

1 × 808 = 808
2 × 808 = 1616
3 × 808 = 2424
...
122 × 808 = 98576
123 × 808 = 99384