What are the numbers divisible by 949?

949, 1898, 2847, 3796, 4745, 5694, 6643, 7592, 8541, 9490, 10439, 11388, 12337, 13286, 14235, 15184, 16133, 17082, 18031, 18980, 19929, 20878, 21827, 22776, 23725, 24674, 25623, 26572, 27521, 28470, 29419, 30368, 31317, 32266, 33215, 34164, 35113, 36062, 37011, 37960, 38909, 39858, 40807, 41756, 42705, 43654, 44603, 45552, 46501, 47450, 48399, 49348, 50297, 51246, 52195, 53144, 54093, 55042, 55991, 56940, 57889, 58838, 59787, 60736, 61685, 62634, 63583, 64532, 65481, 66430, 67379, 68328, 69277, 70226, 71175, 72124, 73073, 74022, 74971, 75920, 76869, 77818, 78767, 79716, 80665, 81614, 82563, 83512, 84461, 85410, 86359, 87308, 88257, 89206, 90155, 91104, 92053, 93002, 93951, 94900, 95849, 96798, 97747, 98696, 99645

There is a total of 105 numbers (up to 100000) that are divisible by 949.
The sum of these numbers is 5281185.
The arithmetic mean of these numbers is 50297.

How to find the numbers divisible by 949?

Finding all the numbers that can be divided by 949 is essentially the same as searching for the multiples of 949: if a number N is a multiple of 949, then 949 is a divisor of N.

Indeed, if we assume that N is a multiple of 949, this means there exists an integer k such that:

$k \times 949 = N$

Conversely, the result of N divided by 949 is this same integer k (without any remainder):

$k = \frac{N}{949}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 949 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 949 less than 100000):

1 × 949 = 949
2 × 949 = 1898
3 × 949 = 2847
...
104 × 949 = 98696
105 × 949 = 99645