What are the numbers divisible by 959?

959, 1918, 2877, 3836, 4795, 5754, 6713, 7672, 8631, 9590, 10549, 11508, 12467, 13426, 14385, 15344, 16303, 17262, 18221, 19180, 20139, 21098, 22057, 23016, 23975, 24934, 25893, 26852, 27811, 28770, 29729, 30688, 31647, 32606, 33565, 34524, 35483, 36442, 37401, 38360, 39319, 40278, 41237, 42196, 43155, 44114, 45073, 46032, 46991, 47950, 48909, 49868, 50827, 51786, 52745, 53704, 54663, 55622, 56581, 57540, 58499, 59458, 60417, 61376, 62335, 63294, 64253, 65212, 66171, 67130, 68089, 69048, 70007, 70966, 71925, 72884, 73843, 74802, 75761, 76720, 77679, 78638, 79597, 80556, 81515, 82474, 83433, 84392, 85351, 86310, 87269, 88228, 89187, 90146, 91105, 92064, 93023, 93982, 94941, 95900, 96859, 97818, 98777, 99736

There is a total of 104 numbers (up to 100000) that are divisible by 959.
The sum of these numbers is 5236140.
The arithmetic mean of these numbers is 50347.5.

How to find the numbers divisible by 959?

Finding all the numbers that can be divided by 959 is essentially the same as searching for the multiples of 959: if a number N is a multiple of 959, then 959 is a divisor of N.

Indeed, if we assume that N is a multiple of 959, this means there exists an integer k such that:

$k \times 959 = N$

Conversely, the result of N divided by 959 is this same integer k (without any remainder):

$k = \frac{N}{959}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 959 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 959 less than 100000):

1 × 959 = 959
2 × 959 = 1918
3 × 959 = 2877
...
103 × 959 = 98777
104 × 959 = 99736