What are the numbers divisible by 960?

960, 1920, 2880, 3840, 4800, 5760, 6720, 7680, 8640, 9600, 10560, 11520, 12480, 13440, 14400, 15360, 16320, 17280, 18240, 19200, 20160, 21120, 22080, 23040, 24000, 24960, 25920, 26880, 27840, 28800, 29760, 30720, 31680, 32640, 33600, 34560, 35520, 36480, 37440, 38400, 39360, 40320, 41280, 42240, 43200, 44160, 45120, 46080, 47040, 48000, 48960, 49920, 50880, 51840, 52800, 53760, 54720, 55680, 56640, 57600, 58560, 59520, 60480, 61440, 62400, 63360, 64320, 65280, 66240, 67200, 68160, 69120, 70080, 71040, 72000, 72960, 73920, 74880, 75840, 76800, 77760, 78720, 79680, 80640, 81600, 82560, 83520, 84480, 85440, 86400, 87360, 88320, 89280, 90240, 91200, 92160, 93120, 94080, 95040, 96000, 96960, 97920, 98880, 99840

There is a total of 104 numbers (up to 100000) that are divisible by 960.
The sum of these numbers is 5241600.
The arithmetic mean of these numbers is 50400.

How to find the numbers divisible by 960?

Finding all the numbers that can be divided by 960 is essentially the same as searching for the multiples of 960: if a number N is a multiple of 960, then 960 is a divisor of N.

Indeed, if we assume that N is a multiple of 960, this means there exists an integer k such that:

$k \times 960 = N$

Conversely, the result of N divided by 960 is this same integer k (without any remainder):

$k = \frac{N}{960}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 960 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 960 less than 100000):

1 × 960 = 960
2 × 960 = 1920
3 × 960 = 2880
...
103 × 960 = 98880
104 × 960 = 99840