What are the numbers divisible by 970?

970, 1940, 2910, 3880, 4850, 5820, 6790, 7760, 8730, 9700, 10670, 11640, 12610, 13580, 14550, 15520, 16490, 17460, 18430, 19400, 20370, 21340, 22310, 23280, 24250, 25220, 26190, 27160, 28130, 29100, 30070, 31040, 32010, 32980, 33950, 34920, 35890, 36860, 37830, 38800, 39770, 40740, 41710, 42680, 43650, 44620, 45590, 46560, 47530, 48500, 49470, 50440, 51410, 52380, 53350, 54320, 55290, 56260, 57230, 58200, 59170, 60140, 61110, 62080, 63050, 64020, 64990, 65960, 66930, 67900, 68870, 69840, 70810, 71780, 72750, 73720, 74690, 75660, 76630, 77600, 78570, 79540, 80510, 81480, 82450, 83420, 84390, 85360, 86330, 87300, 88270, 89240, 90210, 91180, 92150, 93120, 94090, 95060, 96030, 97000, 97970, 98940, 99910

There is a total of 103 numbers (up to 100000) that are divisible by 970.
The sum of these numbers is 5195320.
The arithmetic mean of these numbers is 50440.

How to find the numbers divisible by 970?

Finding all the numbers that can be divided by 970 is essentially the same as searching for the multiples of 970: if a number N is a multiple of 970, then 970 is a divisor of N.

Indeed, if we assume that N is a multiple of 970, this means there exists an integer k such that:

$k \times 970 = N$

Conversely, the result of N divided by 970 is this same integer k (without any remainder):

$k = \frac{N}{970}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 970 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 970 less than 100000):

1 × 970 = 970
2 × 970 = 1940
3 × 970 = 2910
...
102 × 970 = 98940
103 × 970 = 99910