What is 97 mod 5?

How to compute 97 mod 5?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 97 / 5 = 19.4
2. ⌊19.4⌋ = 19 (We only keep the integer part)
3. 5 × 19 = 95
4. 97 - 95 = 2 (Subtracting gives us the remainder)

In short: 97 − (5 × ⌊97 / 5⌋) = 2

Is 97 divisible by 5?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 97 mod 5 is 2, this indicates that dividing 97 by 5 leaves a remainder of 2. Therefore, no, since the remainder isn't zero, 97 is not divisible by 5.